C114门户论坛百科APPEN| 举报 切换到宽版

亚星游戏官网

 找回密码
 注册

只需一步,快速开始

短信验证,便捷登录

搜索

军衔等级:

亚星游戏官网-yaxin222  上等兵

注册:2020-4-214
发表于 2020-6-20 16:40:44 |显示全部楼层
本帖最后由 GeZebra 于 2020-6-20 16:41 编辑

以n78小区(SSB SCS=30kHz)为例,小区搜索中UE解调得到MIB, 假设MIB中定义的pdcch-ConfigSIB1=164,那么根据38.213表13-11, O=5, M=1;可计算得到:
对于SSB0:Type0-PDCCHCSS @ slot10/11 of every even SFN;
对于SSB1:Type0-PDCCHCSS @ slot11/12 of every odd SFN;
对于SSB2:Type0-PDCCHCSS @ slot12/13 of every
even SFN;
对于SSB3:Type0-PDCCHCSS @ slot13/14 of every odd SFN;
对于SSB4:Type0-PDCCHCSS @ slot14/15 of every
even SFN;
对于SSB5:Type0-PDCCHCSS @ slot15/16 of every odd SFN;
对于SSB6:Type0-PDCCHCSS @ slot16/17 of every
even SFN;
对于SSB7:Type0-PDCCHCSS @ slot17/18 of every odd SFN



按照电信2.5ms双周期的配置,此时slot4,8,9,14,18,19都是上行时隙;slot3,7,13,17是S时隙。从以上可见SSB3, SSB4, SSB7对应的Type0-PDCCHCSS落在上行slot.  而在未获得SIB1之前,UE并不清楚该小区的上下行配置。  



请教这种场景下(Type0-PDCCHCSS与UL slot重叠)gNB是如何处理的?








举报本楼

您需要登录后才可以回帖 登录 | 注册 |

手机版|C114 ( 沪ICP备12002291号-1 )|联系大家 |网站地图  

GMT+8, 2024-9-25 05:24 , Processed in 0.388652 second(s), 15 queries , Gzip On.

Copyright © 1999-2023 C114 All Rights Reserved

Discuz Licensed

回顶部
XML 地图 | Sitemap 地图